Question
Question: In the given figure the value of \( \cos ecA \) is  =12
Base (AB) =5
The value of Hypotenuse (AC) is not given in the figure so we first find the hypotenuse by using Pythagoras theorem
We know that by Pythagoras theorem
(hypotenuse)2=(opposie)2+(Adjacent)2
(AC)2=(BC)2+(AB)2
On putting the value of BC and AB from figure
(AC)2=(12)2+(5)2 ----------- (1)
Since (12)2=144 and (5)2=25
On putting this value in the equation (1)
⇒(AC)2=144+25 ⇒(AC)2=169
On taking square root on both side
⇒AC=169
Since 169=13
Therefore AC=13
Hence hypotenuse is 13.
Now, we have to calculating the value of cosecA
Formula for cosecA
cosecA=Oppositehypotenuse
cosecA=BCAC
Since the value of AC=13 and BC=12
On putting this values in above expression
cosecA=1213
Hence, the required value of cosecA is 1213 .
So, the correct answer is “ 1213”.
Note : For this type of problem we must know the property of right angle triangle and also by using the relation between its side we get the formula of all trigonometric ratios like sine, cosine, tangent, cosecant, secant, and cotangent, i.e. they can be written as sin, cos, tan, cosec, sec, and cot. Here we also use Pythagoras theorem which also gives important relation between sides of the right angle triangle.