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Question: In the given figure, if \( PS = 14cm \) , then the value of \( \tan \theta \) is equal to: ![](htt...

In the given figure, if PS=14cmPS = 14cm , then the value of tanθ\tan \theta is equal to:

(A) 43\dfrac{4}{3}
(B) 143\dfrac{{14}}{3}
(C) 53\dfrac{5}{3}
(D) 133\dfrac{{13}}{3}

Explanation

Solution

Hint : tanθ\tan \theta is the ratio of perpendicular to the base. Observe the figure carefully to find the values of the perpendicular or the opposite side. And the base or the adjacent side. Then find their ratio to solve the question.

Complete step-by-step answer :
Observe the diagram

It is given in the question that,
PS=14cmPS = 14cm
From the diagram, we can observe that,
PT=QR=5cmPT = QR = 5cm
And PS=PT+TSPS = PT + TS
14=5+TS\Rightarrow 14 = 5 + TS
Rearranging it we can write
TS=9cmTS = 9cm
Now, in ΔSRT\Delta SRT
We know that the trigonometric ratio of tan is the ratio of perpendicular to the base.
tanθ=TRST\Rightarrow \tan \theta = \dfrac{{TR}}{{ST}} . . . (1)
In ΔPQR\Delta PQR , from the diagram, and by Pythagoras theorem, we can observe that,
PR2=RQ2+PQ2P{R^2} = R{Q^2} + P{Q^2}
By substituting the given values, we get
132=52+PQ2\Rightarrow {13^2} = {5^2} + P{Q^2}
Rearranging it we can write
PQ2=16925=144P{Q^2} = 169 - 25 = 144
PQ2=122\Rightarrow P{Q^2} = {12^2}
PQ=12cmPQ = 12cm
Now, from the diagram, we can observe that,
PQ=TR=12cmPQ = TR = 12cm
By substituting these values in equation (1), we can write
tanθ=129\tan \theta = \dfrac{{12}}{9}
tanθ=43\Rightarrow \tan \theta = \dfrac{4}{3}
Therefore, from the above explanation, the correct answer is, option (A) 43\dfrac{4}{3}
So, the correct answer is “Option A”.

Note : In this question, the most important part was observing the diagram carefully and understanding which side is equal, where will Pythagoras theorem be required etc. The solution was easy, difficult and an important part was how to reach the solution.