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Question

Mathematics Question on Triangles

In the given figure, if AB = c, AC = b and AD 1 BC, then AD =

A

bcb2+c2\frac{bc}{\sqrt{b^2+c^2}}

B

bcb2+c2\frac{bc}{b^2+c^2}

C

b2c2b2+c2\frac{b^2c^2}{\sqrt{b^2+c^2}}

D

None of these

Answer

bcb2+c2\frac{bc}{\sqrt{b^2+c^2}}

Explanation

Solution

The correct option is (A): bcb2+c2\frac{bc}{\sqrt{b^2+c^2}}