Question

In the given figure, equivalent resistance between A and B will be

• A. $\frac{14}{3}\Omega$
• B. $\frac{3}{14}\Omega$
• C. $\frac{9}{14}\Omega$
• D. $\frac{14}{9}\Omega$

Answer 1

Answer: (A)

$\frac{14}{3}\Omega$

Answer 2

Given Wheatstone bridge is balanced because $\frac{P}{Q} = \frac{R}{S}$. Hence the circuit can be redrawn as follows