Question

In the given figure distance of the point from A where the electric field is zero is

• A. 20 cm
• B. 10 cm
• C. 33 cm
• D. None of these

Answer 1

Answer: (C)

33 cm

Answer 2

Suppose electric field is zero at N. Hence

|E_A| = |E_B|

Which gives

$x_{1} = \frac{x}{\sqrt{\frac{Q_{2}}{Q_{1}}} + 1} = \frac{80}{\sqrt{\frac{20}{10}} + 1} = 33cm$