Question

In the given circuit, what will be the equivalent resistance between the points $A$ and $B$ ?

• A. $10/3\, \Omega$
• B. $20/3\, \Omega$
• C. $10/5\, \Omega$
• D. $5\, \Omega$

Answer 1

Answer: (A)

$10/3\, \Omega$

Answer 2

$\because \frac{2}{3}=\frac{4}{6}$
$\therefore$ Given, circuit is a balanced Wheatstone's Bridge.
So, $10\, \Omega$ resistance will be ineffective.
Equivalent resistance of upper arms
$R_{1}=2+3=5\, \Omega$
$\therefore$ Equivalent resistance of lower arms
$R_{2} =4+6=10\, \Omega$
$R_{A B} =\frac{R_{1} R_{2}}{R_{1}+R_{2}}$
$=\frac{5 \times 10}{5+10}$
$=\frac{50}{10}=\frac{10}{3} \Omega$