Question

In the given circuit, the potential of the point E is

• A. Zero
• B.
• C.
• D. 4/3 V

Answer 1

Answer: (C)

Answer 2

The current in the circuit $= \frac { 8 } { 5 + 1 } = \frac { 4 } { 3 }$

Now $V _ { C } - V _ { E } = \frac { 4 } { 3 } \times 1$ ⇒ $V _ { E } = - \frac { 4 } { 3 } V$