Question

In the given circuit switch K is open. The charge on the capacitor is 'C' in steady state is q₁. Now key is closed and steady state charge on C is q₂. The ratio of charges q₁/q₂ is –

• A. 3/2
• B. 3/2
• C. 1
• D. ½

Answer 1

Answer: (A)

3/2

Answer 2

Initially when switch is open

q₁ = CE

Finally when switch is closed

I =; \ V_A – V_B = I 2R = E/3R × 2R = 2E/3

\ Charge on capacitor = CV ; q₂ =

\ = = 3 : 2