Question
Physics Question on Current electricity
In the given circuit diagram, the currents, I1=0.3A,I4=0.8A and I5=0.4A, are flowing as shown. The currents I2,I3 and I6,respectively, are :
A
1.1 A, 0.4 A, 0.4 A
B
-0.4 A, 0.4 A, 1.1 A
C
0.4 A, 1.1 A, 0.4 A
D
1.1 A,-0.4 A, 0.4 A
Answer
1.1 A, 0.4 A, 0.4 A
Explanation
Solution
From KCL,I3=0.8−0.4=0.4A
I2 = 0.4+0.4+0.3
= 1.1A
I6 = 0.4A