Question
Physics Question on electrostatic potential and capacitance
In the given circuit, charge Q2 on the 2μF capacitor changes as C is varied from 1μF to 3μF. Q2 as a function of ′C′ is given properly by (figures are drawn schematically and are not to scale)
A
B
C
D
Answer
Explanation
Solution
q=(C+33C)E
q=CV
q∝C
q2=(C+33C)E(32)
q2=(C+32C)E
q2=(1+C32c)Eq=CV
C↑q2↑
If C→∞,q= constant value.