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Question

Physics Question on electrostatic potential and capacitance

In the given circuit, charge Q2Q_2 on the 2μF2 \mu F capacitor changes as CC is varied from 1μF1 \mu F to 3μF.3 \mu F. Q2Q_2 as a function of C'C' is given properly by (figures are drawn schematically and are not to scale)

A

B

C

D

Answer

Explanation

Solution

q=(3CC+3)Eq=\left(\frac{3 C}{C+3}\right) E
q=CVq=C V
qCq \propto C
q2=(3CC+3)E(23)q _{2}=\left(\frac{3 C }{ C +3}\right) E \left(\frac{2}{3}\right)
q2=(2CC+3)Eq _{2}=\left(\frac{2 C }{ C +3}\right) E
q2=(2c1+3C)Eq=CVq_{2}=\left(\frac{2 c}{1+\frac{3}{C}}\right) E \,\,\,\,\,\,\,q=C V
Cq2C \uparrow q _{2} \uparrow
If C,q=C \rightarrow \infty, q = constant value.