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Question: In the given circuit, a galvanometer with a resistance of is \(0.05 \Omega\), total current measured...

In the given circuit, a galvanometer with a resistance of is 0.05Ω0.05 \Omega, total current measured by this device is

A

0.88 A

B

0.77 A

C

0.55 A

D

0.99 A

Answer

0.99 A

Explanation

Solution

The equivalent circuit of given circuit is given by here

The total resistance in the circuit

R=RS=5Ω=0.05+5=5.05Ω\mathrm { R } = \mathrm { R } _ { \mathrm { S } } = 5 \Omega = 0.05 + 5 = 5.05 \Omega

The current measure by the device

I=VR=55.05=0.99 A\mathrm { I } = \frac { \mathrm { V } } { \mathrm { R } } = \frac { 5 } { 5.05 } = 0.99 \mathrm {~A}