Question

In the Gabriel's phthalimide synthesis, phthalimide is treated first with

• A. $\mathrm { C } _ { 2 } \mathrm { H } _ { 5 } \mathrm { I } / \mathrm { KOH }$
• B. Ethanolic Na
• C. Ethanol and $\mathrm { H } _ { 2 } \mathrm { SO } _ { 4 }$
• D. Ether and $\mathrm { LiAlH } _ { 4 }$

Answer 1

Answer: (A)

$\mathrm { C } _ { 2 } \mathrm { H } _ { 5 } \mathrm { I } / \mathrm { KOH }$

Answer 2

$\mathrm { CH } _ { 3 } \mathrm { COOH } + \mathrm { CHCl } _ { 3 } \rightarrow$ No reaction