Question

In the following sequence of reactions

$CH_{3}CH_{2}CH_{2}Br\overset{\quad KOH(alc)\quad}{\rightarrow}(A)\overset{\quad HBr\quad}{\rightarrow}(B)\overset{\quad KOH(aq.)\quad}{\rightarrow}(C),$ The product (3) is.

• A. Propan – 2 – ol
• B. Propan – l – ol
• C. Propyne
• D. Propene

Answer 1

Answer: (A)

Propan – 2 – ol

Answer 2

CH_{3} - CH - CH_{3}\overset{\quad aq.KOH\quad}{\leftarrow} \\ \overset{|}{OH} \end{matrix}}\begin{matrix} CH_{3} - CH - CH_{3} \\ \overset{|}{Br} \end{matrix}$$