Question
Question: In the following sequence of reaction \(C{H_3} - Br\xrightarrow{{KCN}}A\xrightarrow{{{H_3}{O^ + }...
In the following sequence of reaction
CH3−BrKCNAH3O+BetherLiAlH4C , the end product (C) is
A. Acetone
B. Methane
C. Acetaldehyde
D. Ethyl alcohol
Solution
The given sequence of reaction undergoes various types of reaction that is for obtaining product A it undergoes substitution reaction, for obtaining product B it undergoes hydrolysis and for the end product C it undergoes a reduction reaction.
Complete step-by-step answer: In the given question, we have given a multi step reaction and we have asked to determine the end product C . For calculating the end product we have to solve the reaction step by step. This is as follows given below;
Now, first solve for product A , when methyl bromide reacts with potassium cyanide it undergoes substitution reaction that is bromide substituted by cyanide and we get methyl cyanide. Thus we get product A is methyl bromide. The given reaction below represents the overall reaction
CH3−BrKCNCH3−CN+KBr
For product B,
The product A which is methyl cyanide react with H3O+ it undergoes hydrolysis reaction and give rise to carboxylic acid (CH3COOH) . Thus we get the product B is a carboxylic that is known as acetic acid. The given reaction below represents the overall reaction,
CH3−CNH3O+CH3COOH+HCN
For product C,
The product B which is an acetic acid reaction with LiAlH4 in presence of ether it undergoes reduction and forms ethyl alcohol desired product. Thus we get the product C is ethyl alcohol. The given reaction below represents the overall reaction,
CH3COOHetherLiAlH4C2H5OH+H2O
Hence, the end product C is ethyl alcohol. So the correct answer is D.
Note: It is to be noted that all the given compounds are organic compounds. They have different functional groups attached to it due to different groups present; they have different chemical properties and physical properties.