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Question

Question: In the following sequence of reaction \(C{H_3} - Br\xrightarrow{{KCN}}A\xrightarrow{{{H_3}{O^ + }...

In the following sequence of reaction
CH3BrKCNAH3O+BLiAlH4etherCC{H_3} - Br\xrightarrow{{KCN}}A\xrightarrow{{{H_3}{O^ + }}}B\xrightarrow[{LiAl{H_4}}]{{ether}}C , the end product (C)\left( C \right) is
A.A. Acetone
B.B. Methane
C.C. Acetaldehyde
D.D. Ethyl alcohol

Explanation

Solution

The given sequence of reaction undergoes various types of reaction that is for obtaining product AA it undergoes substitution reaction, for obtaining product BB it undergoes hydrolysis and for the end product CC it undergoes a reduction reaction.

Complete step-by-step answer: In the given question, we have given a multi step reaction and we have asked to determine the end product CC . For calculating the end product we have to solve the reaction step by step. This is as follows given below;
Now, first solve for product AA , when methyl bromide reacts with potassium cyanide it undergoes substitution reaction that is bromide substituted by cyanide and we get methyl cyanide. Thus we get product AA is methyl bromide. The given reaction below represents the overall reaction
CH3BrKCNCH3CN+KBrC{H_3} - Br\xrightarrow{{KCN}}C{H_3} - CN + KBr
For product B,B,
The product AA which is methyl cyanide react with H3O+{H_3}{O^ + } it undergoes hydrolysis reaction and give rise to carboxylic acid (CH3COOH)\left( {C{H_3}COOH} \right) . Thus we get the product BB is a carboxylic that is known as acetic acid. The given reaction below represents the overall reaction,
CH3CNH3O+CH3COOH+HCNC{H_3} - CN\xrightarrow{{{H_3}{O^ + }}}C{H_3}COOH + HCN
For product C,C,
The product BB which is an acetic acid reaction with LiAlH4LiAl{H_4} in presence of ether it undergoes reduction and forms ethyl alcohol desired product. Thus we get the product CC is ethyl alcohol. The given reaction below represents the overall reaction,
CH3COOHLiAlH4etherC2H5OH+H2OC{H_3}COOH\xrightarrow[{LiAl{H_4}}]{{ether}}{C_2}{H_5}OH + {H_2}O
Hence, the end product CC is ethyl alcohol. So the correct answer is D.D.

Note: It is to be noted that all the given compounds are organic compounds. They have different functional groups attached to it due to different groups present; they have different chemical properties and physical properties.