Question

In the following reactions:

X and Y are:

Answer 1

To answer this question, you must recall the mechanism of the reduction reaction of ketones with sodium borohydride followed by hydrolysis to yield alcohols. The use of deuterium in place of hydrogen does not affect the reaction occurring.

Complete answer:
Sodium borohydride is used for taking aldehydes and ketones, one rung down the oxidation ladder, i.e. from carbonyl group to alcoholic group. Let us discuss the mechanism of this reduction reaction:
The reaction takes place in two steps. In the first step, the borohydride on, releases a hydride ion which because of the negative charge is a nucleophile. The carbonyl carbon, i.e. the carbon atom bonded to oxygen is electrophilic in nature due to the higher electronegativity of oxygen atom. Thus, it is susceptible to nucleophilic attack and is attacked by the hydride ion. Thus, the carbon hydrogen bond is formed and the carbon oxygen double bon becomes a single bond with oxygen carrying a negative charge.
In the second step, i.e. introduction of acid, protonation occurs and the alkoxide is protonated to an alcohol. So, we can see that the hydrogen bonded to carbon comes from sodium borohydride and the hydrogen in hydroxyl group comes from the acid. So X and Y are:

Note:
Sodium borohydride is a good reducing agent and is a source of hydride ion. Although it is not as powerful a reducing agent as lithium aluminium hydride, it is a very effective reagent for carrying out the reduction of carbonyl compounds aldehydes and ketones to alcohols. It does not reduce esters or carboxylic acids or amides.