Question

In the following reaction X is.

$CH_{3}NH_{2} + X + KOH \rightarrow CH_{3}NC(\text{highly offensive odour})$.

• A. $CH_{2}Cl_{2}$
• B. $CHCl_{3}$
• C. $CH_{3}Cl$
• D. $CCl_{4}$

Answer 1

Answer: (B)

$CHCl_{3}$

Answer 2

$CH_{3}NH_{2} + \underset{(X)}{CHCl_{3}} + 3KOH \rightarrow 3KCl + CH_{3}NC + 3H_{2}O$