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Question: In the following reaction the value of ‘X’ is \[7N^{14} +_{2} ⥂ He^{4} \rightarrow X +_{1} ⥂ H^{1}\...

In the following reaction the value of ‘X’ is

7N14+2⥂He4→X+1⥂H17N^{14} +_{2} ⥂ He^{4} \rightarrow X +_{1} ⥂ H^{1}

A

8N178N^{17}

B

8O178O^{17}

C

7O167O^{16}

D

7N167N^{16}

Answer

8O178O^{17}

Explanation

Solution

7N14+2He4→8O17+1H17N^{14} +_{2}He^{4} \rightarrow_{8}O^{17} +_{1}H^{1}