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Question: In the following reaction, \[{\text{C}}{{\text{H}}_3}C{H_2}C{H_2}Br\xrightarrow{{NaCN}}X\xrightarrow...

In the following reaction, CH3CH2CH2BrNaCNXH3O+YH+CH3CH2OHZ{\text{C}}{{\text{H}}_3}C{H_2}C{H_2}Br\xrightarrow{{NaCN}}X\xrightarrow{{{H_3}{O^ + }}}Y\xrightarrow[{{H^ + }}]{{C{H_3}C{H_2}OH}}Z, identify X, Y and Z.
A.
B. CH3CH2CH2CH=NOCH2CH3C{H_3}C{H_2}C{H_2}CH = NOC{H_2}C{H_3}
C. CH3CH2CH2CH(OCH2CH3)2C{H_3}C{H_2}C{H_2}CH{\left( {OC{H_2}C{H_3}} \right)_2}
D.

Explanation

Solution

CH3CH2CHBrC{H_3}C{H_2}CHBr is a halo alkane, going under a series of reactions to form an and product. It is a three step reaction involving substitution reaction, hydroxylation in presence of acidic medium and then esterification reaction.
Complete step by step answer: CH3CH2CHBrC{H_3}C{H_2}CHBr is an haloalkane going through given steps of reaction.
Step I :- CH3CH2CHBrC{H_3}C{H_2}CHBrreacting with NaCN.NaCN. NaCNNaCN is present as Na+N{a^ + }and CN.  CN^ - CN.{\;^ - }CNis a nucleophile that attacks on the carbon of CH3CH2CHBrC{H_3}C{H_2}CHBr, proceeding with substitution reaction

Step II :- when this cyanide compound reacts with H2O+{H_2}{O^ + } in presence of heat, it forms a carboxylic acid.

Step III :- Then, this carboxylic acid compound is treated with an alcohol, CH3CH2OHC{H_3}C{H_2}OH in acidic medium. We know that the reaction of alcohol and carboxylic acid produces an ester by undergoing an esterification reaction.

The IUPACIUPAC name of compound zz is Ethyl but anoate.
Ethyl but anoate is commonly used as an artificial flowering agent similar to orange juice. It is also used in alcoholic beverages like martinis. Ethyl butyrate is one of the most preferred fragrance and flavoring agents.
So, the correct answer is “Option D”.

Note: Esterification reaction in the question took place as shown below