Question
Question: In the following reaction, \[{\text{C}}{{\text{H}}_3}C{H_2}C{H_2}Br\xrightarrow{{NaCN}}X\xrightarrow...
In the following reaction, CH3CH2CH2BrNaCNXH3O+YCH3CH2OHH+Z, identify X, Y and Z.
A.
B. CH3CH2CH2CH=NOCH2CH3
C. CH3CH2CH2CH(OCH2CH3)2
D.
Solution
CH3CH2CHBr is a halo alkane, going under a series of reactions to form an and product. It is a three step reaction involving substitution reaction, hydroxylation in presence of acidic medium and then esterification reaction.
Complete step by step answer: CH3CH2CHBr is an haloalkane going through given steps of reaction.
Step I :- CH3CH2CHBrreacting with NaCN. NaCN is present as Na+and −CN.−CNis a nucleophile that attacks on the carbon of CH3CH2CHBr, proceeding with substitution reaction
Step II :- when this cyanide compound reacts with H2O+ in presence of heat, it forms a carboxylic acid.
Step III :- Then, this carboxylic acid compound is treated with an alcohol, CH3CH2OH in acidic medium. We know that the reaction of alcohol and carboxylic acid produces an ester by undergoing an esterification reaction.
The IUPAC name of compound z is Ethyl but anoate.
Ethyl but anoate is commonly used as an artificial flowering agent similar to orange juice. It is also used in alcoholic beverages like martinis. Ethyl butyrate is one of the most preferred fragrance and flavoring agents.
So, the correct answer is “Option D”.
Note: Esterification reaction in the question took place as shown below