Question

In the following reaction

Fe₃O₄ + $MnO_{4}^{-}$¾® Fe₂O₃ + MnO₂

the number of moles of OH^– liberated as per the balanced equation in the basic medium is-

• A. 1
• B. 2
• C. 3
• D. 4

Answer 1

Answer: (B)

2

Answer 2

Fe₃O₄ and $MnO_{4}^{-}$ react in 6 : 2 mole ratio in the balanced chemical equation

6Fe₃O₄ +$2MnO_{4}^{-}$ + H₂O ¾®

9Fe₂O₃ + 2MnO₂ + OH^–

By balancing the residual charge with OH^–

6Fe₃O₄ + $2MnO_{4}^{-}$ + H₂O ¾®

9Fe₂O₃ + 2MnO₂ + 2 OH^–