Question

In the following reaction
$aX\rightarrow bY\ \ log_{10}(\frac{dx}{dt})=log_{10}(\frac{dy}{dt})+0.4771$
X and Y respectively can be
[Given: log3=0.4771]

• A. C2H2 and C6H6
• B. Pentane and 2, 2-Dimethylpropane
• C. O2 and O3
• D. N2O4 and NO2

Answer 1

Answer: (A)

C2H2 and C6H6

Answer 2

The correct option is (A) : C2H2 and C6H6