Question
Question: In the following reaction \(12Mg^{24} +_{2}He^{4} \rightarrow_{14}Si^{X} +_{0}n^{1},X\)is....
In the following reaction
12Mg24+2He4→14SiX+0n1,Xis.
A
28
B
27
C
26
D
22
Answer
27
Explanation
Solution
x+1= 24 + 4 ⇒ x = 27.
In the following reaction
12Mg24+2He4→14SiX+0n1,Xis.
28
27
26
22
27
x+1= 24 + 4 ⇒ x = 27.