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Question: In the following common emitter configuration an NPN transistor with current gain β = 100 is used. T...

In the following common emitter configuration an NPN transistor with current gain β = 100 is used. The output voltage of the amplifier will be

A

10 Mv

B

0.1 V

C

1.0 V

D

10 V

Answer

1.0 V

Explanation

Solution

Voltage gain =Output voltageInput voltage= \frac{\text{Output voltage}}{\text{Input voltage}}

⇒ Vout = Vin × Voltage gain

⇒ Vout = Vin × Current gain × Resistance gain

= Vin × β × RLRBE\frac{R_{L}}{R_{BE}}= 10−3×100×101=1V.10^{- 3} \times 100 \times \frac{10}{1} = 1V.