Question
Physics Question on Current electricity
In the following common emitter circuit, if β = 100, VCE = 7V, VBE = Negligible and RC = 2 kΩ, then IB is equal to
A
(A) 0.01 mA
B
(B) 0.04 mA
C
(C) 0.02 mA
D
(D) 0.03 mA
Answer
(B) 0.04 mA
Explanation
Solution
Explanation:
Considering the output circuit, we haveVCC=iCRC+VCEiCRC=15−7=8VHence, iC=8RC=82×103=4mAiB=ICβ=4×10−3100=0.04m.A