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Question: In the following circuit *E*<sub>1</sub> = 4*V*, *R*<sub>1</sub> = 2Ω *E*<sub>2</sub> = 6*V*, *R*<s...

In the following circuit E1 = 4V, R1 = 2Ω

E2 = 6V, R2 = 2Ω and R3 = 4Ω. The current i1 is

A

1.6 A

B

1.8 A

C

2.25 A

D

1 A

Answer

1.8 A

Explanation

Solution

For loop (1) 2i1−i2=22 i _ { 1 } - i _ { 2 } = 2 … (i)

For loop (2) 3i2−i1=33 i _ { 2 } - i _ { 1 } = 3 … (ii)

After solving equation (i) and (ii) we get and