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Question: In the following circuit diagram inductive reactance of inductor is 24Ω and capacitive reactance of ...

In the following circuit diagram inductive reactance of inductor is 24Ω and capacitive reactance of capacitor is 48Ω, then reading of ammeter will be

A

5 A

B

2.4 A

C

2.0 A

D

10 A

Answer

5 A

Explanation

Solution

iL=24024=10Ai_{L} = \frac{240}{24} = 10A

iC=24048=5Ai_{C} = \frac{240}{48} = 5A

Hence i=iLiC=5Ai = i_{L} - i_{C} = 5A