Question

In the following circuit $C_1=12 \mu F, C_2=C_3=4 \mu F$ and $C_4=C_5=2 \mu F$.The Charge stored in $C_3$ is ___$\mu C$

Answer 1

As per given in the loop 1234,
$+6-\frac{48}{12}-\frac{q_3}{4}=0$,
So, q1 = 12 (6 - 2)
= 48 μC
Therefore , q3 = 8 μC