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Question: In the following circuit a 10 m long potentiometer wire with resistance 1.2 ohm/m, a resistance R<su...

In the following circuit a 10 m long potentiometer wire with resistance 1.2 ohm/m, a resistance R1 and an accumulator of emf 2 V are connected in series. When the emf of thermocouple is 2.4 mV then the deflection in galvanometer is zero. The current supplied by the accumulator will be

A

4 × 10–4A

B

8 × 10–4A

C

4 × 10–3A

D

8 × 10–3A

Answer

4 × 10–4A

Explanation

Solution

E=xl=iρlE = x l = i \rho l

i=Eρl=Eρl=2.4×1031.2×5=4×104 Ai = \frac { E } { \rho l } = \frac { E } { \rho l } = \frac { 2.4 \times 10 ^ { - 3 } } { 1.2 \times 5 } = 4 \times 10 ^ { - 4 } \mathrm {~A}.