Question
Physics Question on laws of motion
In the first second of its flight, rocket ejects 1/60 of its mass with a velocity of 2400ms−1 . The acceleration of the rocket is:
A
19.6ms−2
B
30.2ms−2
C
40ms−2
D
49.8ms−2
Answer
40ms−2
Explanation
Solution
Thrust force on the rocket
Ft=vr(−dtdm)
or ma=vr(−dtdm)
where vr is the exhaust velocity of gases and
−dtdm is the mass of the ejected per unit time.
Given, vr=2400ms−1,−dtdm=601kg/s
m=1kg
Substituting the values in above relation
1×a=2400×601
or a=40ms−2