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Question: In the final answer of the expression \(\frac{(29.2 - 20.2)(1.79 \times 10^{5})}{1.37}\). The numbe...

In the final answer of the expression

(29.2−20.2)(1.79×105)1.37\frac{(29.2 - 20.2)(1.79 \times 10^{5})}{1.37}. The number of significant figures is.

A

1

B

2

C

3

D

4

Answer

2

Explanation

Solution

(29.2−20.2) 6mu(1.79×105)1.37=9.0×1.79×1051.37\frac{(29.2 - 20.2)\mspace{6mu}(1.79 \times 10^{5})}{1.37} = \frac{9.0 \times 1.79 \times 10^{5}}{1.37}

Least precise terms i.e., 9.0 has only two significant figures. Hence, final answer will have two significant figures.