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Question

Physics Question on Semiconductor electronics: materials, devices and simple circuits

In the figures shown below

A

In both Fig. (a) and Fig. (b) the diodes are forward based

B

In both Fig. (a) and Fig. (b) the diodes are reverse biased

C

In Fig- the diode is forward biased and in Fig. the diode is reverse biased

D

In Fig, the diode is reverse biased and in Fig. it is forward biased

Answer

In Fig- the diode is forward biased and in Fig. the diode is reverse biased

Explanation

Solution

The density of d=MVd=\frac{M}{V} Error of density d=ΔMM×100+ΔVV×100d=\frac{\Delta M}{M}\times 100+\frac{\Delta V}{V}\times 100 =0.0122.42×100+0.14.7×100=\frac{0.01}{22.42}\times 100+\frac{0.1}{4.7}\times 100 =0.044+2.127=0.044+2.127 =2.2=2.2% (approximately)