Solveeit Logo

Question

Question: In the figure, the wedge is pushed with an acceleration of 10\(\sqrt { 3 }\)m/s<sup>2</sup>. It is s...

In the figure, the wedge is pushed with an acceleration of 103\sqrt { 3 }m/s2. It is seen that the block starts climbing upon the smooth inclined face of wedge. What will be the time taken by the block to reach the top ?

A

25\frac { 2 } { \sqrt { 5 } } s

B

15\frac { 1 } { \sqrt { 5 } } s

C

5\sqrt { 5 } s

D

52\frac { \sqrt { 5 } } { 2 } s

Answer

15\frac { 1 } { \sqrt { 5 } } s

Explanation

Solution

acceleration of block relative to wedge,

= a cos q – g sin q (up the plane)

= 10 ( 3\sqrt { 3 } ) (32)\left( \frac { \sqrt { 3 } } { 2 } \right) – 10 (12)\left( \frac { 1 } { 2 } \right)

Then l = 12\frac { 1 } { 2 } anet t2