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Question

Physics Question on Electric charges and fields

In the figure, the inner (shaded) region AA represents a sphere of radius rA=1r_A=1, within which the electrostatic charge density varies with the radial distance rr from the center as ρA=kr\rho_A=k r, where kk is positive. In the spherical shell BB of outer radius rBr_B, the electrostatic charge density varies as ρB=2kr\rho_B=\frac{2 k}{r}. Assume that dimensions are taken care of. All physical quantities are in their SI units.
sphere of radius
Which of the following statement(s) is(are) correct?

A

If rB=32r_B=\sqrt{\frac{3}{2}}, then the electric field is zero everywhere outside BB.

B

If rB=32r_B=\frac{3}{2}, then the electric potential just outside BB is kϵ0\frac{k}{\epsilon_0}.

C

If rB=2r_B=2, then the total charge of the configuration is 15πk15 \pi k.

D

If rB=52r_B=\frac{5}{2}, then the magnitude of the electric field just outside BB is 13πkϵ0\frac{13 \pi k}{\epsilon_0}.

Answer

If rB=32r_B=\sqrt{\frac{3}{2}}, then the electric field is zero everywhere outside BB.

Explanation

Solution

The correct answer is (B): If rB=32r_B=\frac{3}{2}, then the electric potential just outside BB is kϵ0\frac{k}{\epsilon_0}.