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Question: In the figure, the block A, B and C of mass \(m\) each, have acceleration \({a_1}\), \({a_2}\) and \...

In the figure, the block A, B and C of mass mm each, have acceleration a1{a_1}, a2{a_2} and a3{a_3} respectively. F1{F_1} and F2{F_2} are external forces of magnitude 2  mg2\;mg and mgmg respectively. Then

(a) a1=a2=a3{a_1} = {a_2} = {a_3}
(b) a1a3a2{a_1}\rangle {a_3}\rangle {a_2}
(c) a1=a2{a_1} = {a_2}, a2a3{a_2}\rangle {a_3}
(d) a1a2{a_1}\rangle {a_2}, a2=a3{a_2} = {a_3}

Explanation

Solution

We will use Newton's law for the determination of the acceleration of the various blocks. In Newton's law, use the magnitude of the net force for the calculation of the acceleration. We will apply Newton's law on each block separately so that we can get information about the sequence of the accelerations.

Complete step by step answer:
It is given in the question that magnitudes of the forces F1{F_1} and F2{F_2} is 2  mg2\;mg and mgmg, and acceleration of the blocks A, B and C are a1{a_1}, a2{a_2} and a3{a_3}. We will use this information in the calculation of acceleration of blocks.
First, we will apply Newton's law on block A.
Therefore, we get
Fnet=ma1 F1mg=ma1 \Rightarrow {F_{net}} = m{a_1}\\\ \Rightarrow {F_1} - mg = m{a_1}
It is given in the question that the magnitude of the force F1{F_1} is 2mg2mg, so substitute value of F1{F_1} in the above equation.
2mgmg=ma1 mg=ma1 a1=g \Rightarrow 2mg - mg = m{a_1}\\\ \Rightarrow mg = m{a_1}\\\ \Rightarrow {a_1} = g
Now we will apply Newton's law on block B.
Therefore, we get
Fnet=ma2 2mgmg=(2m+m)a2 mg=3ma2 a2=g3 \Rightarrow {F_{net}} = m{a_2}\\\ \Rightarrow 2mg - mg = (2m + m){a_2}\\\ \Rightarrow mg = 3m{a_2}\\\ \Rightarrow {a_2} = \dfrac{g}{3}
Again, we will apply Newton's law on block C.
Therefore, we get
F2+mgmg=(m+m)a3 F2=2ma3\Rightarrow {F_2} + mg - mg = (m + m){a_3}\\\ \Rightarrow {F_2} = 2m{a_3}
It is given in the question that the magnitude of the force F2{F_2} is mgmg, so substitute the value of F2{F_2} in the above equation.
mg=2ma3 a3=g2 \Rightarrow mg = 2m{a_3}\\\ \Rightarrow {a_3} = \dfrac{g}{2}
Therefore, the accelerations of block A, B and C are gg, g/3g/3 and g/2g/2, so the sequence of the accelerations of the blocks are a1a3a2{a_1}\rangle {a_3}\rangle {a_2} and option (b) is correct.

Note: In this solution, the determination of the net force is the main thing. Here, additional load or force is applied on the other side of the block. So, for the determination of the magnitude of the net force on the block, we will resolve the forces. After getting the net force, we can easily put the given values for the calculation of acceleration.