Question

In the figure shown, the total resistance between A and B is

• A. $12\Omega$
• B. $4\Omega$
• C. $6\Omega$
• D. $8\Omega$

Answer 1

Answer: (D)

$8\Omega$

Answer 2

The last two resistances are out of circuit. Now $8\Omega$ is in parallel with$(1 + 1 + 4 + 1 + 1)\Omega$.

$\therefore R = 8\Omega||8\Omega = \frac{8}{2} = 4\Omega$ ⇒ $R_{AB} = 4 + 2 + 2 = 8\Omega$