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Question

Question: In the figure shown the acceleration of A is \(\overrightarrow { \mathrm { a } } _ { \mathrm { A } }...

In the figure shown the acceleration of A is aA\overrightarrow { \mathrm { a } } _ { \mathrm { A } } = 15 i^\hat { \mathbf { i } } + 15 j^\hat { \mathrm { j } } , then the acceleration of B is (A remains in contact with B) –

A

6 i^\hat { \mathbf { i } }

B

–15 i^\hat { \mathbf { i } }

C

–10 i^\hat { \mathbf { i } }

D

–5 i^\hat { \mathbf { i } }

Answer

–5 i^\hat { \mathbf { i } }

Explanation

Solution

From wedge constraint

(aA)1 = (aB)1

aAx cos 530 – aAy cos 370

̃ aB cos 530 aB

= – 5 m/s

aB\overrightarrow { \mathrm { a } } _ { \mathrm { B } } = –5 i^\hat { \mathbf { i } }