Question
Question: In the figure shown the acceleration of A is \(\overrightarrow { \mathrm { a } } _ { \mathrm { A } }...
In the figure shown the acceleration of A is aA = 15 i^ + 15 j^ , then the acceleration of B is (A remains in contact with B) –
A
6 i^
B
–15 i^
C
–10 i^
D
–5 i^
Answer
–5 i^
Explanation
Solution
From wedge constraint
(aA)1 = (aB)1
aAx cos 530 – aAy cos 370
̃ aB cos 530 aB
= – 5 m/s
aB = –5 i^