Question

In the figure shown below, the terminal voltage across ${{E}_{2}}$ is

• A. 12 V
• B. 12.66 V
• C. 11.34 V
• D. 11.66 V

Answer 1

Answer: (C)

11.34 V

Answer 2

Net voltage $=12-8=4\text{ }V$
Net resistance $=9+2+1=12\,\Omega$
Current through the circuit
$=\frac{4}{12}=\frac{1}{3}A$
Terminal voltage across
${{E}_{2}}$ is $={{E}_{2}}-I{{r}_{2}}=12-\frac{1}{3}\times 2$
$=12-\frac{2}{3}=\frac{34}{3}=11.34\,V$