Question

In the figure shown below, the charge on the left plate of the $10 \; \mu F$ capacitor is $-30 \; \mu C$ . The charge on the right plate of the $6 \; \mu F$ capacitor is :

• A. $- 18 \; \mu C$
• B. $- 12 \; \mu C$
• C. $+ 12 \; \mu C$
• D. $+ 18 \; \mu C$

Answer 1

Answer: (D)

$+ 18 \; \mu C$

Answer 2

$6 \mu F \; \& \; 4\mu F$ are in parallel & total charge on this combination is $30 \; \mu C$
$\therefore$ Charge on $6 \mu F$ capacitor $= \frac{6}{6+4} \times 30$
$= 18 \, \mu C$
Since charge is asked on right plate therefore is $+18 \mu C$