Question

In the figure given below, the end B of the rod AB which makes angle q with the floor is pulled with a constant velocity v₀ as shown. The length of rod is l. At an instant when q = 37ŗ

• A. Velocity of end A is $\frac{4v_{0}}{3}$
• B. Angular velocity of rod is $\frac{5v_{0}}{6\mathcal{l}}$
• C. Angular velocity of rod is constant
• D. Velocity of end A is constant

Answer 1

Answer: (A)

Velocity of end A is $\frac{4v_{0}}{3}$

Answer 2

x² + y² = l²

Ž $\frac{dy}{dt}$ = – $\frac{dx}{dt}$

\ v_A = – $\frac{4}{3}$v­₀

Now, x = l cos q

$\frac{dx}{dt}$= – l sinq$\frac{d\theta}{dt}$ Ž w = – $\frac { 5 } { 3 }$ $\left( \frac{v_{0}}{\mathcal{l}} \right)$