Question

In the figure circuit, if E = 10 V, R₁ = 2 ohm, R₂ = 3 ohm,

R₃ = 6 ohm and L = 5 henry. The current I₁ just after pressing the switch S is –

• A. (10/4) ampere
• B. (10/5) ampere
• C. (10/12) ampere
• D. (10/6) ampere

Answer 1

Answer: (B)

(10/5) ampere

Answer 2

i = $\frac { E } { R _ { 1 } + R _ { 2 } }$ = $\frac { 10 } { ( 2 + 3 ) }$ = $\frac { 10 } { 5 }$ Amp