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Question

Physics Question on Current electricity

In the experiment to determine the galvanometer resistance by half-deflection method, the plot of 1θ\frac{1}{ \theta} vs the resistance (R) of the resistance box is shown in the figure. The figure of merit of the galvanometer is .............. ×10–1 A/division. [The source has emf 2V]
Figure

Answer

Using the equation:

i=Kθ,i = K\theta,

At half deflection:

2G+R=Kθ.\frac{2}{G + R} = K\theta.

Rearranging:

1θ=(G+R)K2=RK+GK2.\frac{1}{\theta} = \frac{(G + R)K}{2} = RK + \frac{GK}{2}.

From the slope of the graph:

Slope=K=0.5=5×101A/division.\text{Slope} = K = 0.5 = 5 \times 10^{-1} \, \text{A/division}.