Question

In the equilibrium ⇌ , the extent

of dissociation of water when p = 1 atm and

$K = 2.08 \times 10 ^ { - 3 }$ is approximately

• A. 2%
• B. 0.2%
• C. 20%
• D. 1%

Answer 1

Answer: (A)

2%

Answer 2

For the equilibrium

$K _ { p } = \frac { \alpha ^ { 3 / 2 } P ^ { 1 / 2 } } { \sqrt { 2 } } P = 1 \mathrm {~atm}$

$\alpha = \left( \sqrt { 2 } \cdot K _ { p } \right) ^ { 2 / 3 } = 0.0205 \approx 2 \%$