Question

In the equilibrium

$CH_{3}COOH + HF$ ⇄ $CH_{3}COO{H_{2}}^{+} + F^{-}$

• A. $F^{-}$is the conjugate acid of $CH_{3}COOH$
• B. $F^{-}$is the conjugate base of $HF$
• C. $CH_{3}COOH$ is the conjugate acid of $CH_{3}COO{H_{2}}^{+}$
• D. $CH_{3}COO{H_{2}}^{+}$ is the conjugate base of $CH_{3}COOH$

Answer 1

Answer: (B)

$F^{-}$is the conjugate base of $HF$

Answer 2

$CH_{3}COOH + HF$ ⇌$CH_{3}COOH_{2}^{+} + F^{-}$.$HF$ gives $H^{+}$ to the $CH_{3}COOH$. So it is a conjugate base of HF.