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Question

Chemistry Question on Electrochemistry

In the electrolysis of acidulated water, it is desired to obtain 1.12cc1.12\, cc of Hydrogen per second under S.T.P.S.T.P. condition. The current to be passed is

A

19.3Amp19.3\, Amp

B

0.965Amp0.965\, Amp

C

1.93Amp1.93\, Amp

D

9.65Amp9.65\, Amp

Answer

9.65Amp9.65\, Amp

Explanation

Solution

No. of moles of H2=1.1222400H _{2}=\frac{1.12}{22400}

No. of equivalence of hydrogen

=1.12×222400=104=\frac{1.12 \times 2}{22400}=10^{-4}

No. of Faradays required =104=10^{-4}
\therefore\,\,\, Current to be passed in one second

=96500×104=96500 \times 10^{-4}
=9.65A=9.65\, A