Question

In the electrochemical cell :
$Zn|ZnSO_4(0.01M)||CuSO_4(1.0 M)|Cu,$
the emf of this Daniel cell is $E_1$. When the concentration of $ZnSO_4$ is changed to 1.0 M and that of $CuSO_4$ changed to 0.01 M, the emf changes to $E_2$. From the following, which one is the relationship between $E_1$ and $E_2$?
(Given, $\frac {RT}{F}= 0.059$)

• A. $E_1 = E_2$
• B. $E_1 < E_2$
• C. $E_1 > E_2$
• D. $E_2=0 ≠ E_1$

Answer 1

Answer: (C)

$E_1 > E_2$

Answer 2

The correct option is (C): $E_1 > E_2$.