Question

In the diagram shown find the potential at point A.

• A. Zero
• B. 2 V
• C. 4 V
• D. 6 V

Answer 1

Answer: (A)

Zero

Answer 2

E_Net = 21V, R_Net = 21Ω

∴ I_Net = $\frac{E_{Net}}{R_{Net}}$ = $\frac{21}{21}$ = 1A

Now V_A – V_B = + 6 – 1 × 6 + 5 – 1 × 5 + 4 – 1 × 4

V_A–V_B=0 (and since V_B = 0 ) (∴ V_A is also 0)