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Question

Physics Question on System of Particles & Rotational Motion

In the diagram shown below all three rods are of equal length LL and equal mass MM. The system is rotated such that rod BB is the axis. What is the moment of inertia of the system?

A

ML26\frac{ML^{2}}{6}

B

43ML2\frac{4}{3}ML^{2}

C

ML23\frac{ML^{2}}{3}

D

23ML2\frac{2}{3}ML^{2}

Answer

ML26\frac{ML^{2}}{6}

Explanation

Solution

Since the width is negligible, the moment of inertia of B is zero along its length. IA+IC=mL212+mL212mL26I_{A}+I_{C}=\frac{mL^{2}}{12}+\frac{mL^{2}}{12}-\frac{mL^{2}}{6}