Question

In the condenser show in the circuit is charged to 5V and left in the circuit, in 12 s the charge on the condenser will become–

• A. $\frac{10}{e}$C
• B. $\frac{e}{10}$C
• C. $\frac{10}{e^{2}}$
• D. $\frac{e^{2}}{10}$C

Answer 1

Answer: (A)

$\frac{10}{e}$C

Answer 2

During discharge

q_c =

= 2 × 5 $\left( e ^ { - \frac { 12 } { 12 } } \right)$

= $\frac { 10 } { \mathrm { e } }$