Question

In the compounds $KMnO_{4}$ and $K_{2}Cr_{2}O_{7},$ the highest oxidation state is of the element:

• A. $Mn$
• B. $K$
• C. $O$
• D. $Cr$

Answer 1

Answer: (A)

$Mn$

Answer 2

Mn has $+7$ oxidation state in $KMnO _{4}$ $1 +n+4(-2) =0$ $1+n-8 =0$ $n =+7$