Physics Question on Semiconductor electronics: materials, devices and simple circuits

Question

In the common emitter configuration of n-p-n transistor $10^{10}$ electrons enter the emitter in 1 $\mu s$ and 2% of the electrons are lost to the base, the current gain of the amplifier is

Answer 1

Solution

$I_{b}=2 \%$ of $I_{e},$ $I_{c}=90 \%$ of $I_{e},$ $\beta=?$ $\beta=\frac{I_{c}}{I_{b}}=\frac{98 \% \text { of } I_{e}}{2 \% \text { of } I_{b}}=49$