Solveeit Logo

Question

Question: In the co-axial system of circle\(x ^ { 2 } + y ^ { 2 } + 2 g x + c = 0\) where g is a parameter, if...

In the co-axial system of circlex2+y2+2gx+c=0x ^ { 2 } + y ^ { 2 } + 2 g x + c = 0 where g is a parameter, if c> 0. Then the circles are

A

Orthogonal

B

Touching type

C

Intersecting type

D

Non intersecting type

Answer

Non intersecting type

Explanation

Solution

The equation of a system of circle with its centre on the axis of x is x2+y2+2gx+c=0x ^ { 2 } + y ^ { 2 } + 2 g x + c = 0. Any point on the radical axis is (0,y1)\left( 0 , y _ { 1 } \right)

Putting, x = 0, y=±cy = \pm \sqrt { - c }

If c is positive (c >0), we have no real point on radical axis, then circles are said to be non-intersecting type